-5p^2+200p=0

Solution for -5p^2+200p=0 equation:

-5p^2+200p=0

a = -5; b = 200; c = 0;
Δ = b2-4ac
Δ = 2002-4·(-5)·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200}{2*-5}=\frac{-400}{-10}
=+40
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200}{2*-5}=\frac{0}{-10}
=0
$